That got me thinking this evening and I did some geometric-trigonometric sketches of the forces applied on a bridge by the strings and I came to some...interesting? results
1) Tension of the strings (forward on T) is the same at both sides of the bridge
2) T (and T') can be separated into two components: one horizontal and one vertical (Th and Tv). First one is parallel to the top, the other one perpendicular to to it (same goes for Th' and Tv' on the other side)
3) Tv and Tv' are downward forces and add themselves resulting in the downward force over the bridge and top.
4) Th and Th' are opposed forces which withdraw each other being Th always greater. That generates an horizontal force on the bridge top that pulls it towards the neck side. It is canceled however by friction between bridge and strings
5) Tv and Tv' magnitude depends on the angles formed between the strings and each side of the bridge: The smaller the angle the greater the force
...In short, the downward force on the bridge and top comes from the strings tension and it depends on the angle between the bridge and the strings
Happy with that finding I went on thinking because my two cellos have a rather low neck step over the top plate and both have too a very low neck projection onto the bridge.
Doing some more geometric-trigonometric sketches of the strings tension on the neck I came to the conclusion that:
6) The smaller the angle formed between the neck and the neck root the greater the force that pulls the neck up on its end at the pegbox
7) Angles described on points 5) and 7) are related so that the smaller the one the smaller the other.
Summarizing:
To decrease both the force of the bridge over the top plate and the force that pulls the pegbox up, the neck must be fitted so that those two angles are the greater as possible










